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60x^2+3x-36=0
a = 60; b = 3; c = -36;
Δ = b2-4ac
Δ = 32-4·60·(-36)
Δ = 8649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8649}=93$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-93}{2*60}=\frac{-96}{120} =-4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+93}{2*60}=\frac{90}{120} =3/4 $
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